WebThe near point of a hypermetropic eye is 1 m. What is the power of lens required to correct this defect? (the near piont of a normal eye is 25 cm) Hypermetropia is a defect of vision in which a person is not able to see objects close to the eye clearly. It can be corrected using a suitable convex lens. WebOct 9, 2024 · for a hypermetropic eye u=-25cm and v=-50cm. substituting in the lens formula we get focal length is f=50cm =0.5m. from the formula P=1/f. P=1/0.5 2D. so the power of the lens is 2 dioptre and the nature of lens is a converging lens or a convex lens

The near point of a hyper metropic person is 50 cm from …

WebSep 26, 2024 · To treat hypermetropic eye, convex lens is used to focus the object kept at 30 cm to the point 60 cm , which is ner point of this case. we have lens equation :- (1/v) - … ray roe obituary phoenix arizona

The Near-point of a Person Suffering from Hypermetropia …

WebMar 12, 2024 · Near point of hypermetropic eye = 0.5m = 0.5 x 100 = 50cm. Near point of normal eye = 0.25m =0.25 x 100 = 25cm. So, v = -50cm. u = 25cm. So by lens formula:-So … WebIn the ray diagram of the Hypermetropic eye, the image of a nearby object (object is a minimum distance of vision i.e. at D=25cm) is formed behind the retina. The near-point of … WebSolution Given, Image distance, v = -50 cm Object distance, u = -25 cm From the lens formula We know, 1 f = 1 v− 1 u Putting all the values 1 f = − 1 50+ 1 25 After solving f = 50cm = … ray rogers ocean city